km). In
terms of light years, one parsec = 3.26 light years. We
can measure shifts to 1/50 arc seconds
50 parsecs in
distance.
,
where
is the
radius of the sphere. Amount of energy passing through sphere
surface = flux
surface area. So sphere-1 flux
=
sphere-2 flux
flux-1 =
flux-2
.
The inverse square law! The flux is the amount of energy reaching each
square centimeter of a detector (eg., your eye, CCD, piece of the sphere) every
second.
Most famous apparently bright stars are intrinsically bright (luminous). Most
nearby stars are intrinsically faint. Assume we live in typical patch of galaxy
(Copernican principle)
most stars are puny emitters of light. Faintest
stars have absolute magnitudes = 19, brightest stars have absolute magnitudes =
-8
huge range in luminosity!
``Distance modulus'' = app. mag. - abs. mag. =
.
So the ratio of two stars luminosities is
.
Remember the more luminous star has an absolute magnitude that is less
than a fainter star's absolute magnitude!
Star App.Mag. Distance(pc) Abs.Mag. Luminosity(rel. to Sun)
Sirius -1.4 2.7 1.4 23 Arcturus 0 11.0 -0.2 100 Vega 0 8.1 0.5 52 Spica 1 80.0 -3.4 1900 Barnard's Star 9.5 1.8 13.3 1/2500 Proxima Centauri 11.0 1.3 15.5 1/19000
such that
(
is the speed of light).
Amount of shift depends on the speed of the object relative to observer.
Red-shift
object is moving away; blue-shift
object is moving toward you. This only gives us speed along the
line-of-sight. To get the tangential speed, we need to measure angular
speed of star across the sky
and
determine the star's distance
.
Then
where
is a
conversion factor that will take care of the conversion from arc seconds and
parsecs to kilometers/second.
(C.M. distance 1) = (mass star 2)
(C.M. distance 2)
or the point they would be balanced upon if the stars were on a stellar seesaw.
Heavy star closer to C.M. than light star. Kepler's 3rd law: (mass 1 + mass 2)
=
if use
solar masses, A.U. for the distance from the C.M.
and years for the
orbital period
.
Distance a = C.M.-distance-1 + C.M.-distance-2. C.M.-distance = velocity
orbit period /
so use doppler
shifts of spectral lines. Remember these rules:
velocity1 = mass2
velocity2
no
absorption. If the star's
temperature is too low, then there are not many electrons in 2nd energy
level--most in ground state because there are not that many atomic collisions.
To produce absorption lines in visible spectrum, need electrons in 2nd energy
level.
Color Class Temperature Prominent Lines
bluest O 40,000 ionized Helium bluish B 18,000 neutral Helium, neutral Hydrogen blue-white A 10,000 neutral Hydrogen white F 7,000 neutral Hydrogen, ionized Calcium yellow-white G 5,500 neutral Hydrogen, strongest ionized Calcium orange K 4,000 neutral metals (Calcium, iron), ionized Calcium red M 3,000 molecules and neutral metals
. The H-R
diagram below is for all stars visible to the naked
eye (down to apparent magnitude = +5) plus all stars within 25 parsecs.
Watts/cm
). Bulb's
luminosity is 100 Watts. Use Inverse Square Law to find out bulb's distance.
last updated 27 Oct 95
(206) 543-1979
University of Washington
Astronomy
Box 351580
Seattle, WA 98195-1580